Oblicz: $\sqrt(32)$+$\sqrt(50)$-$\sqrt(72)$=

Zadanie dodane przez UW21 , 24.10.2011 14:43
Oblicz:
$\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt(32)}$+$\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt(50)}$-$\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt(72)}$=

$\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{32}}$ + $\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{50}}$ - $\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{72}}$ = $\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{16 * 2}}$ + $\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{25 * 2}}$ - $\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{36 * 2}}$ = 4$\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{2}}$ + 5$\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{2}}$ - 6$\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{2}}$ = 3$\png \definecolor{mgray}{RGB}{47,47,47}\color{mgray}{\sqrt{2}}$