rozwiąż nierówność: a)−2(x−2)(x+1)≥3 b)2(x−1)x−5(1−x)x≤7 c)64(2x−1)$a^{2}$−49(3−2x)$a^{2}$≥0

a)
−2(x−2)(x+1)≥3
(x-2)(x+1)<=-
-x-<=0
=1+2=3
\Delta=
=\sqrt{3} v =\sqrt{3}

b)
2(x−1)x−5(1−x)x≤7
2(x^{2})<=7
2x^{2}<=7
7x^{2}-x-1<=0
=1+4=5
\Delta=
=\sqrt{5} v =\sqrt{5}