Wyłącz wspólny czynnik poza nawias: a) (1-5x)(x+2)+(5x-1)(8-2x) b)(1-x)(x-5)+(1-x)(x+3) x)3(5x+2)-3(2x+1)(-5x-2)

(1-5x)(x+2)+(5x-1)(8-2x)=(1-5x)(x+2)+(5x-1)*2*(4-x)=(-1)(5x-1)(x+2)+(5x-1)*2*(4-x)=(5x-1)*[-(x+2)+2(4-x)]=(5x-1)(-x-2+8-2x)=(5x-1)(-3x+6)=-3(5x-1)(x-2)

b)(1-x)(x-5)+(1-x)(x+3)=(1-x)[(x-5)+(x+3)]=(1-x)(x-5+x+3)=(1-x)(2x-2)=2(1-x)(x-1)

c)3(5x+2)(3+3(2x+1)=(5x+2)(3+6x+3)=(5x+2)(6x+6)=6(5x+2)(x+1)